The vertex form of the equation of a parabola y=(x-3)^+36

So the vertex is (3,36)

Step-by-step explanation:

y = a (x-h)^2 +k  is the vertex form of a parabola

(h,k) is the vertex

Assuming the equation is

y = (x-3)^2 +36

h = 3 and k = 36

So the vertex is (3,36)

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}