What is the probability of rolling a four given two six sided dice? 3/36

what is the probability that a player can roll a four 3 times in a row (assume that rolling the dice each time does not affect the outcome of the next roll)?

You have the right idea for the first part. There are three ways to add to 4, and those ways are: 1+3 = 4, 2+2 = 4, and 3+1 = 4. This is out of 6*6 = 36 ways to roll two dice. That leads to 3/36. You then reduce the fraction 3/36 to get 1/12. Divide both parts by 3 to reduce.

So the first answer is 1/12

The first answer is used to help find the second answer. The probability of getting a single "4" is 1/12, so the probability of getting three "4"s in a row is (1/12)^3 = (1/12)*(1/12)*(1/12) = 1/1728

Second answer is 1/1728

for the first question it would be the second answer for the second question it would be the third answer and for the third question it would be the first answer

step-by-step explanation: