Can anyone me asap plzz. solve the inequality k + 6 ≤ 21; (a)k ≥ 27 (b)k ≤ 15 (c)k ≥ 15 (d)k ≤ 27

Solve the inequality k + 6 ≤ 21;

(A)k ≥ 27

(B)k ≤ 15

(C)k ≥ 15

(D)k ≤ 27

Step-by-step explanation:

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

answer: what statements

step-by-step explanation if you write the statements down then i could you.