Use the grouping method to factor the polynomial below completely. x3 + 2x2 + 3x + 6

Hello from MrBillDoesMath!

(x+2) ( x^2 + 3)

Discussion:

x^3 + 2x^2 + 3x + 6 =  

( x^3 + 2x^2) + (3x + 6) =         => factor "x^2" from the first term; factor 3

                                                    from the second term

x^2( x + 2) + 3( x+2)  =             => factor (x+2) from each term

(x+2) ( x^2 + 3)

Thank you,

MrB

answer: idk

step-by-step explanation: