You invested $6000 in two accounts paying 7% and 9% annual interest. at the end of the year, the total interest from these investments was $510. how much was invested at each rate?

The amount invested at 7% was $1,500 and the amount invested at 9% was $4,500

Step-by-step explanation:

we know that

The simple interest formula is equal to

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem

Let

x-----> the amount invested at account paying 7%

(6,000-x) -----> the amount invested at account paying 9%

substitute in the formula above

Solve for x

therefore

The amount invested at 7% was $1,500 and the amount invested at 9% was $4,500

cut 138 centimeters off

step-by-step explanation:

250-112 = 138

y -5 = (-1/4)(x + 8)

step-by-step explanation: