3/4, 1, 5/4 find the 22nd & 43rd terms

6 and 45/4

Step-by-step explanation:

If the first three terms of your sequence are 3/4, 1, 5/4, the first term is obviously 3/4 and the common difference is 1/4.  This is an arithmetic sequence.

We can write a general formula for the nth term of this sequence as follows:

a(n) = a(1) + (n-1)(1/4), or, since a(1) = 3/4,

a(n) = 3/4 + (n-1) / 4

Then a(22) = 3/4 + (22-1)/4, or 3/4 + 21/4, or 24/4, or just 6.

a(43) = 3/4 + (43-1)/4, or 3/4 + 42/4, or 45/4.

your answer is the last one

step-by-step explanation:

divide the length of a'c' by the length of ac to get a scale factor of two

& then reflect vertically (over the y-axis)

so your answer is dilation by a scale factor of 2 followed by reflection over the y-axis

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629