Joseph has $10,000 to invest. he can go to yankee bank that pays 5% simple interest or met bank that pays 4% interest compounded annually. at how many years will met bank be the better choice?

After 12 years ( approx )

Step-by-step explanation:

Let after t years the amount in met bank will exceed to the amount in Yankee bank,

For Yankee bank,

The principal amount, P = $ 10,000

Simple annual interest rate, r = 5 %

Hence, the amount in this bank after x years,

Now, For Met bank,

The principal amount, P = $ 10,000

Compound annual interest rate, r = 4 %

Hence, the amount in this bank after x years,

⇒For exceeding,

By the below graph, the above condition occurs after intersection of and at (11.919, 15959.341)

Hence, after x = 11.919 ≈ 12 years the amount in Met bank will be greater than that of Yankee bank.

⇒ For 12 years Met Bank will be the better choice.

answer:

1. 0.04

2. 0.15

step-by-step explanation:

i just finished that assignment for properties of probability distributions.

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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