Let u = < -5, -9> , v = < 6, 8> . find -8u - 2v.

The value of -8u-2v is:

28i+56j or in vector form it is: <28,56>

Step-by-step explanation:

We are given two vectors u and v such that:

u = <-5, -9> and v = <6, 8>.

In vector form it could be represented as:

u=-5i-9j, where i and j represents the unit vector in the direction of x and y axis respectively.

and v=6i+8j

Now we are asked to find the value of:

-8u - 2v.

We know that -8u could be written as:

-8u=-8(-5i-9j)

⇒ -8u=(-8)×(-5)i+(-8)×(-9)j

⇒ -8u=40i+72j

Also -2v is given as:

-2v=-2(6i+8j)

⇒  -2v= (-2)×6i+(-2)×8j

⇒  -2v= -12i-16j

Hence the value of -8u - 2v is:

-8u-2v= 40i+72j-12i-16j

⇒   -8u-2v= 28i+56j

Hence in vector form it could be written as:

<28,56>.

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

step-by-step explanation:

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