An object is attached to a spring that is stretched and released. the equation d=-8cos(pi/6 t) models the distance, d, of the object in inches above or below the rest position as a function of time, t, in seconds. approximately when will the object be 6 inches above the rest position? round to the nearest hundredth, if necessary.

a)0 seconds
b)1.38 seconds
c)4.62 seconds
d)8 seconds

4.62

Step-by-step explanation:

using the distance formula plug in the 6

6=-8cos(pi/6 t)

Option C - 4.62 seconds

Step-by-step explanation:

Given : An object is attached to a spring that is stretched and released. The equation models the distance, d, of the object in inches above or below the rest position as a function of time, t, in seconds.

To find : When will the object be 6 inches above the rest position?  

Solution :

We have given the model,

Where, d is the distance of the object in inches above or below the rest position and t is a function of time in seconds.

We have to find the time at which the object be 6 inches above the rest position i.e, for d=6.

Firstly we plot the graph of the given model,

Refer the attached graph below.

Now, the object be 6 inches above the rest position i.e, for d=6.

The time is t=4.62 seconds.

Therefore, Option C is correct.

the mean and mad

step-by-step explanation:

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: