If c and k are the roots of 6-x-x^2=0 find c + k. pls solve like a quadratic equation

c + k = - 1

Step-by-step explanation:

given a quadratic equation in standard form : ax² + bx + c = 0 : a ≠ 0

Then the sum of the roots = - and

The product of the roots =

- x² - x + 6 = 0 is in standard form

with a = - 1, b = - 1 and c = 6

The roots are c and k, hence

c + k = - = - 1

answer: 59

step-by-step explanation:

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068