Brainliest + points ( explain)

calculate the total payback for a $2,500 loan at 9% annual interest for two years.

use the formula,
m
=
p
m
(
1
+
m
)
n
a
(
1
+
m
)
n
a
−
1
as needed.

a.
$1,021.80

b.
$1,370.52

c.
$2,043.60

d.
$2,741.04

$2970.25

Step-by-step explanation:

Please write the formula all on one line:

M = P(1 + r)^n, where P is the principal, r is the annual interest rate as a decimal fraction and n is the number of years.

Here, that comes to:

M = $2,500(1 + 0.09)^2, or

    = $2,500 (1.09)^2, or

M   = $2,500(1.1881), or

M = $2970.25.

$2970.25 will be needed to pay back this $2,500 loan.

the image of (6, 9) under a dilation is (4, 6). the scale factor is

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2