Si el pentagono abcde es congruente al pentagono fghis entonces cual es la medida de hi

Si el pentágono ABCDE es congruente con el pentágono FGHIS, entonces la medida de HI es congruente con la medida de CD

Step-by-step explanation:

Los polígonos congruentes tienen ángulos correspondientes A = F, B = G, C = H, D = I, E = J.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23