The length of a rectangle is 5 minutes longer than its with if the perimeter of the rectangle must be at least 34 units what are the possible lamps of the rectangle right in any quality to represent the problem then solve the inequality

w ≥ 6

l ≥ 11

Step-by-step explanation:

The perimeter of a rectangle is equal to P = 2l+2w where l=length and w=width. Here the length is 5 feet longer than the width or 5+w. This means the width is w. Substitute P = 34, l=5+w and w into the perimeter equation. Then solve for w.

34 ≤ 2*(5+w) + 2w

34 ≤ 10+2w+2w

34 ≤ 10+4w

24 ≤ 4w

6 ≤ w

This means the width must be at least 6 so the solution is w ≥ 6.

To find the length substitute 6 into l ≤ 5+w.

l ≤ 5 + 6

l ≤ 11

The length is l ≥ 11.

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!