Jordan has 10 candies in a bowl. thee are 3 blue candies 2 red candies and the rest are green

5 green candies, Or 9/100 for a finished result from a probability question

Step-by-step explanation:

If you want the full question, its "Jordan has 10 candies in a bowl. There are 3 blue candies, 2 red candies, and the rest are green. Without looking, he grabs one candy, puts it back, and then grabs another candy.

What is the probability that both candies he grabs are blue?"

We can basically use logic to say that all the other options, (1/5, 3/50, & 1/15) are wrong. 1/5 is wrong because there are more than five candies in the bag. 3/50 is wrong because you have ten choices, and out of these choices each one has ten variables, so it makes it a total of 100 choices. 1/15 is wrong for the same reason as 1/5.

rotated. i took the test

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !