Suppose a figure is located in quadrant i. which of the following sequences will result in an image that is located in quadrant iv?
a. rotate 360 degrees counterclockwise, then shift 1 unit up
b. rotate 180 degrees counterclockwise, then shift 1 unit down
c. rotate 90 degrees counterclockwise, then shift 1 unit up
d. rotate 270 degrees counterclockwise, then shift 1 unit down

Option b is right

Step-by-step explanation:

Given that a figure is located in Quadrant I.

The figure is transformed and the image is located in quadrant iv.

We have to select the option which would have resulted in this.

A) rotating 360 degrees would result in the same place i.e. I quadrant hence wrong.

B) rotating 180 degrees counterclockwise, will make y coordinate negative but x coordinate will remain as it is.

Hence we get image in the IV quadrant.

THis option is correct

C) Rotating90 degrees counterclockwise will not transform all the coordinates to the IV quadrant hence wrong

D) Rotating 270 degrees counterclockwise would make the image in III quadrant hence wrong

So option b is right.

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

just keep asking questions until you have a better understanding.

step-by-step explanation: