Akangaroo hopped \dfrac13 3 1 ? of the distance to the lake with her baby in her pouch. she hopped the remaining 70407040 yards without her baby in her pouch. how many miles did the kangaroo hop to the lake?

6 miles.

Step-by-step explanation:

Let x be the total distance hoped by Kangaroo to the lake.

We have been given that a kangaroo hopped 1/3 of the distance to the lake with her baby in her pouch.

She hopped the remaining 7040 yards without her baby in her pouch. This means that 2/3 of total distance (x) is 7040. We can represent this information in an equation as:

Let us solve for x by multiplying both sides of our equation by 3/2.

Therefore, the total distance hoped by the kangaroo is 10560 yards.

1 mile = 1760 yards

Let us convert this distance in miles by dividing 10560 yards by 1760.

Therefore, the kangaroo hoped 6 miles to the lake.

21/58.

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hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)