Work out the length of am, then find the area of the triangle.
* refer to image below*

see explanation

Step-by-step explanation:

ΔABC is isosceles and AM is the perpendicular bisector to BC, hence

BM = MC = 4 cm

Using Pythagoras' identity on ΔABM, then

AB² = AM² + BM², that is

7² = AM² + 4²

49 = AM² + 16 ( subtract 16 from both sides )

33 = AM² ( take the square root of both sides )

AM =

The area (A) of ΔABC is found using

A = bh ( b is the base BC and h the height AM )

A = × 8 × = 4 cm² ≈ 23 cm²

it would to have a graph or something ! but i had this question so its false

step-by-step explanation:

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x