The length of a side of a rectangle is 6 cm. what should the length of the other side be so that the perimeter of the rectangle is smaller than the perimeter of a square with a side of 4 cm?

width < 2 cm

Step-by-step explanation:

The formula for the perimeter of a rectangle is:

P = 2w + 2l, where 'w'=width and 'l'=length

The forumla for the perimeter of a square is:

P = 4s, where 's'=length of one side

The perimeter of a square with side of 4cm: P=4(4) = 16cm

Since the length of the rectangle = 6cm, we can set up an inequality to find the measure of the other side:

2w + 2(6) < 16 or 2w + 12 < 16

Subtract 12 from both sides: 2w + 12 - 12 < 16 - 12 or 2w < 4

Divide and solve:  2w/2 < 4/2 or w < 2 cm

b

step-by-step explanation:

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: