James walked around two rectangular parks one measures 5423 cm by 3978 cm and the other measures 2903 cm by 1846 cm how far did he walk

james brother walk around at different park that is 8012 cm by 3456 cm what is the difference in the distance each one walked

Part a) James walked

Part b) The difference in distance each one walked is

Step-by-step explanation:

we know that

The perimeter of a rectangle is equal to

step 1

Find the perimeter Park 1

Find the perimeter Park 2

To calculate how far James walked, sum the perimeter park 1 and the perimeter Park 2

so

step 2

James brother

Find the perimeter of the different park

step 3

Find the difference in distance each one walked

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

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step-by-step explanation: