Plz fast

given angle 1 = angle 2,

find x.

x=6

Step-by-step explanation:

Since the angles are the same , we can use the angle bisector theorem

3           x

=

x-4            4

Using cross products

3*4 = x(x-4)

Distriubte

12 = x^2 -4x

Subtract 12 from each side

12-12 = x^2 -4x-12

0 = x^2 -4x-12

Factor

0 = (x-6) (x+2)

Using the zero product property

x-6 = 0   x+2 =0

x=6    x=-2

But x cannot be negative since it is a length

x=6

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

whats the