In the equation ( ax+3)²=36, a is a constant. if x = -3 is one solution to the equation, what is a possible value of a?

a = -1 or 3

Step-by-step explanation:

( ax+3)²=36

We will let x =-3

( -3a+3)²=36

Take the square root of each side

sqrt( ( -3a+3)²)=±sqrt(36)

( -3a+3)=±6

-3a +3  = 6                     -3a+3 = -6

Subtract 3 from each side

-3a +3-3 = 6-3               -3a+3-3 = -6-3

-3a = 3                            -3a =-9

Divide by -3

-3a/-3 = 3/-3                     -3a/-3 = -9/-3

a = -1                                        a =3

a can be either -1 or 3

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

what are you trying to solve here

step-by-step explanation: