Solve to find x and y in the diagram. asap! i don't

  x = 12; y = 7.5

Step-by-step explanation:

The arrows on the lines that appear to be parallel mean the lines actually are parallel. The square corner at bottom right means that angle is a right angle, 90°. Since the lines are parallel, the measures of angles made by the right-angle transversal are all equal and all have measure 90°.

That is ...

  (12y)° = 90°

  90/12 = y = 7.5 . . . . . divide by 12°, the coefficient of y

Using this value in the expression for the corresponding 90° angle, you get ...

  (5x +4·7.5)° = 90°

  5x = 60 . . . . . . . . . . divide by °, subtract 30

  60/5 = x = 12 . . . . . .divide by the coefficient of x

For this problem, you are supposed to realize that corresponding angles have the same measure (where a transversal crosses parallel lines) and that all the angles are 90° (when lines meet at right angles).

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.