Y=2x-4 and y=x-2. solve the system of equation, show work

x=2

Step-by-step explanation:

Since y is equal to y set the two equations equal to each other to get only one variable. Simplify by using subtraction or addition to get the x by itself. So add 4 to the other side to get the regular numbers by itself, then subtract 1x to the other side and you get. X=2

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.