If (x-3) is one factor of x^2+x-12, then what is the other factor?

x-4
4x-3
3x-4
x+

(x + 4)

Step-by-step explanation:

x^2+x-12

= x^2 + 4x -3x -12

= x(x + 4) - 3(x + 4)

= (x + 4)(x - 3)

So factors: (x + 4) and (x - 3)

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

the answer will be the last one