What is a quartic polynomial function in standard form with zeros -3. 1, 3

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x^4 - x^3 - 9 x^2 + 9 x

Discussion:

A Quartic polynomial is of degree 4. The polynomial is:

(x-0)(x- (-3))(x-1)(x-3) =

x^4 - x^3 - 9 x^2 + 9 x

Thank you,

MrB

The polynomial would be x^3 - x^2 - 9x + 9

Step-by-step explanation:

In order to find this, we first need to find the multiplied factors. To get those, we simply write each term as being equal to x and then solve for 0.

x = -3

(x + 3) = 0

x = 1

(x - 1) = 0

x = 3

(x - 3) = 0

Now we multiply the 3 parenthesis together in any order.

(x + 3)(x - 3)(x - 1)

(x^2 - 9)(x - 1)

x^3 -x^2 - 9x + 9

answer: what is the question you're trying to ask?

step-by-step explanation: