(1,1) is a solution for the system

x+2y=3

5x-3y=2

question 4 options:

truefalse

question 5 (1 point)

if the first step of solving

x+3y=5

2x-1=y

is x+3(2x-1)=5 we solve it by

True

Step-by-step explanation:

1+2*1=3

5*1-3*1=2

1+2=3

5-3=2

3=3

2=2

answer: dead jah

step-by-step explanation:

bullet + jah= dead jah

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.