Aball is dropped from the top of a building. the distance in feet above the ground, represented by h(t), after t seconds can be modeled by the equation h(t)=-16t^2+180.
what is it's height after 3 seconds of falling?

324 feet

Step-by-step explanation:

h(3) = 16(3)^2 + 180

h(3) = 16(9) + 180

h(3) = 144 + 180

h(3) = 324

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

lol we need to see what the question is asking about

step-by-step explanation: