Which quadratic equation is equivalent to (x + 2)2 + 5(x + 2) – 6 = 0?
(u + 2)2 + 5(u + 2) – 6 = 0 where u = (x – 2)
u2 + 4 + 5u – 6 = 0 where u = (x – 2)
u2 + 5u – 6 = 0 where u = (x + 2)
u2 + u – 6 = 0 where u = (x + 2)

u2 + 5u – 6 = 0 where u = (x + 2

Step-by-step explanation:

Answered by - RealStephani

#MARKASBRAINLIEST?

Choice C is correct answer.

Step-by-step explanation:

We have given a quadratic equation.

A quadratic equation is an equation of second degree.its standard form is ax²+bx+c = 0 where a,b and c are constants and x is variable.

(x+2)²+5(x+2)-6 = 0

We have to rewrite given quadratic equation by subtituting u = x+2.

Putting u = x+2 in given quadratic equation,we get

u²-5u-6 = 0 is also a quadratic equation which is equivalent to (x+2)²+5(x+2)-6 = 0 ,where u = (x+2).

Hence,Choice C is our answer.

4400

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3