Can someone show work for these problems will give ! emergency

Part 1)

Part 2)  

Part 3)

Part 4)  

Part 5)

Part 6)  

Part 7)  

Part 8)

Part 9)

Part 10)

Part 11)

Part 12)

Step-by-step explanation:

Part 1)  

Subtract 4 both sides

Divide by 2 both sides

the solution is the interval ------> [10,∞)

The solution is the shaded area to the right of the solid line at number 10 (closed circle).

see the attached figure  

Part 2)  

Adds 3 both sides

Multiply by 3 both sides

the solution is the interval ------> (-∞,-9]

The solution is the shaded area to the left of the solid line at number -9 (closed circle).

see the attached figure  

Part 3)  

applying the distributive property left side

adds 3 both sides

Multiply by -1 both sides

Divide by 3 both sides

the solution is the interval ------> [5,∞)

The solution is the shaded area to the right of the solid line at number 5 (closed circle).

see the attached figure

Part 4)  

applying the distributive property left side  

Subtract 16 both sides  

Multiply by -1 both sides

Divide by 4 both sides

the solution is the interval ------> (-∞,-10)

The solution is the shaded area to the left of the dashed line at number -10 (open circle).

see the attached figure

Part 5)

adds 2 both sides

Multiply by -1 both sides

the solution is the interval ------> (-∞,-10)

The solution is the shaded area to the left of the dashed line at number -10 (open circle).

Part 6)

applying the distributive property left side  

adds 12 both sides

multiply by -1 both sides

divide by 4 both sides

the solution is the interval ------> (-∞,5)

The solution is the shaded area to the left of the dashed line at number 5 (open circle).

see the attached figure

Part 7)

Subtract 4 both sides

Multiply by 3 both sides

the solution is the interval ------> (-∞,6)

The solution is the shaded area to the left of the dashed line at number 6 (open circle).

see the attached figure  

Part 8)

applying the distributive property left side

subtract 12 both sides

divide by -1 both sides

divide by 3 both sides

the solution is the interval ------> (-∞,4]

The solution is the shaded area to the left of the solid line at number 4 (closed circle).

see the attached figure  

Part 9)  

Adds 7 both sides

Multiply by -1 both sides

Divide by 7 both sides

the solution is the interval ------> [7,∞)

The solution is the shaded area to the right of the solid line at number 7 (closed circle).

see the attached figure  

Part 10)  

applying the distributive property left side

subtract 21 both sides

Multiply by -1 both sides

the solution is the interval ------> (-∞,0]

The solution is the shaded area to the left of the solid line at number 0 (closed circle).

see the attached figure  

Part 11)  

Adds 4 both sides

Multiply by -1 both sides

Divide by 11 both sides

the solution is the interval ------> (-∞,1)

The solution is the shaded area to the left of the dashed line at number 1 (open circle).

see the attached figure

Part 12)  

Multiply by 15 both sides

Adds 9 both sides

the solution is the interval ------> (24,∞)

The solution is the shaded area to the right of the dashed line at number 24 (open circle).

see the attached figure

i get you, what you should do is think of the positive things that would come out of it. it will make yours parents proud and raise your grade. you should always try and if you can't focus tell the teacher.

to complete this square you have to rotate about the origin 270 degrees clockwise.