Find the value of x in pythagorean theorem.

Hello from MrBillDoesMath!

x = 21.93   (approx)

Discussion:

The two small triangles are congruent by ASA (each contains a right angle and equal base angles as the large triangle is isosceles). Applying Pythagoras gives

20^2 + (18/2)^2 = x^2                = > as 20^2 = 400 and 9^2 = 81

400   + 81           = x^2               =>

x^2 = 481                                    => take the square rot of both sides

x = 21.93   (approx)

Thank you,

MrB

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step-by-step explanation: