∆abc is reflected across the x-axis and translated 2 units up to give the image ∆a'b'c' with coordinates a'(1, 1), b'(2, -1), c'(2, 1). what are the coordinates of the preimage ∆abc? a. a(-1, 1), b(-2, 3), c(-2, 1) b. a(1, 1), b(2, 3), c(2, 1) c. a(1, -3), b(2, -1), c(2, -3) d. a(1, -3), b(2, -5), c(2, -3)

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

36

step-by-step explanation:

think the answer would beb