What is the nth term rule of the linear sequence below? 27 , 25 , 23 , 21 , 19 , . .

 The required n-th term is 25+2n.

Step-by-step explanation:  We are given to find the n-th term of the following linear sequence :

27,   25,   23,   21,   19,   .   .    .

We note from the given sequence that

So, the given sequence is an arithmetic sequence with first term 27 and common difference, 2.

We know that the n-th term of an arithmetic sequence with first term a and common difference d is given by

For the given sequence, we have

a = 27  and  d = 2.

Therefore, the n-th term of the given sequence is

Thus, the required n-th term is 25+2n.

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.