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Mathematics, 21.06.2019 15:00 rosezgomez97

The radical equation 2+√2x-3 = √x+7 has a solution set [x= a0} and an extraneous root x = a1.

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The radical equation 2+√2x-3 = √x+7 has a solution set [x= a0} and an extraneous root x = a1....
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