Me with this one question, and i'll upvote the brainliest answer

  " x = 12 " .

________________________________________________

Step-by-step explanation:

________________________________________________

Note: If 2 (two) triangles are "similar" ;  then their corresponding sides are "proportional".

________________________________________________

Since one of the sides [the "hypotenuse"] of one the triangles given ; shows the measurement containing an expression with a value of "x" — specifically;  " 6x + 28 " ;  

    →  And since we want to solve for the value of "x" ;  we  use this "hypotenuse" of said particular triangle to set up a "proportion" with corresponding sides; so we can solve for "x" :

→  Set up proportions as a "ratio" ; or fraction:

       →  7:28::25:(6x + 28) ;  Solve for "x" ;

Let us write this in the form of a "fraction" :

      →   ;

________________________________________________

Note:  

        →  Rewrite:  " " ; by simplifying to:

                                    " " ;

________________________________________________

         →  Since:  " " ;

              =  " (7÷7) / (28÷7) " ;

              =  " (1 /4) " ;

              =   " " .

________________________________________________

Now, rewrite the "proportion" ; as follows:

________________________________________________

         ;

________________________________________________

Now:   "Cross multiply" ;  that is:

______________________________________

→   Given:   " " ;  

         and:  " b0 " ;  " d0 " ;

→  Then:   " a * d "  =  " b * c " .

________________________________________________

Likewise:   " 1(6x + 28)  =  (4) * (25) "   ;

______________________________________________

SImplify:    " 6x + 28 =  100 " ;  Solve for "x" ;

→ Subtract "28" from each side of the equation:

                  →   " 6x + 28 - 28 = 100 - 28 "  ;

    to get:   →   " 6x  =  72  "  ;

Now, divide each side of the equation by:  " 6 " ;

        to isolate "x" on one side of the equation; & to solve for "x" ; as follows:

   →   "  6x  =  72  "  ;

         →   6x / 6  =  72 / 6 ;

  to get:

         →   " x  = 12 "  ;

        →   which is the answer.

______________________________________________

Hope this helps!

  Best wishes in your academic pursuits

          — and within the "" community!

______________________________________________

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~