Solve 2^x=32 and rewrite this equation in a logarithmic form

x=5

x = log2(32)

Step-by-step explanation:

2^x=32

Rewrite 32 as 2^5

2^x = 2^5

Since the bases are the same, the exponents have to be the same

x=5

2^x=32

Take log base 2 on each side

log2(2^x) = log2(32)

x = log2(32)

the answer to the question is a

step-by-step explanation:

it has the same slope and the same y-intercept.

y + 11 = -7/9(x - 18)

y + 11 =-7/9x + 14

b

y = -7/9x + 3

y-intercept (0, 3)

the first one, all those points on the line just make a strait line.