Need an artist designed a badge for a school club. figure abcd on the coordinate grid below shows the shape of the badge: the badge is enlarged and plotted on the coordinate grid as figure jklm with point j located at (2, -2) and point m is located at (5, 4). which of these could be the coordinates for point l? a. (2, 4) b. (8, 4) c. (5, 1) d. (5, 7)
AD is enlarged to JM
AD² = 2² + 1² = 4 + 1 =5
AD = √5
then you plug in JM
JM² = 6² + 3² = 36 + 9 = 45
JM = √45 = 3 √5
ML= 3 DC
then you add
the coordinates for point L are (8, 4)
Option B is right.
Given that an artist designed a badge for a school club.
ABCD is given in the picture.
If JKLM is enlargement of ABCD, then scale factor would b the ratio of AD to JM
Scale factor = 3
AB = 3 hence JK = 9
DC = 1 and so ML = 3
ML is parallel to x axis with a distance of 3 units.
COordinates of L = (5+3, 4) = (8,4)
Option B is right
The correct option is d.
It is given that the figure JKLM is image of ABCD. So the side MJ is the image of DA.
From the figure it is noticed that the A(-8,5) and D(-7,7).
Distance formula is
The points of image are J(-6,-8) and M(-3,-2).
The scale factor is,
Therefore the corresponding sides of image are 3 times more than the preimage.
From the figure it is noticed that the distance between DC is 1 units.
Since the sides ML is image of DC, therefore the length of ML is 3 units.
The point C is 1 unit right from D, therefore the point L is 3 unit right from M. The y coordinate of M and L are same. To find the x coordinate of L we have to add 3 units in x coordinate of M.
Therefore the option d is correct.