Amodel rocket is launched from a roof into a large field. the path of the rocket can be modeled by the equation y = -0.04x^2 + 8.6x + 4.8, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. how far horizontally from its starting point will the rocket land? a. 0.56 m b. 215.56 m c. 431.11 m d. 215.74 m
Option b. 215.56 is the right answer.
Path of the rocket can be modeled by the equation y = -0.04x²+8.6x+4.8
Here y represents the vertical height of the rocket and x represents the horizontal distance in meters.
We have to calculate the horizontal distance covered by the rocket.
Now we can say when rocket is landing y = 0 or vertical distance of the rocket will be zero.
Then equation will be
-.04x²+8.6x+4.8 = 0
the area is multiplying all the given measurements together.
40 * 18 * 30 * 24 = 518,400
since it took 13times to completely subtract it hence its square root is 13