Given that sin∅ = 1/4, 0 < ∅ < π/2, what is the exact value of cos∅? a. (√4)/4 b. (√15)/4 c. (4π)/2 d. (4√2)/4

b

Step-by-step explanation:

Using the trigonometric identity

• sin²x + cos²x = 1 , hence

cosx = ±

cosΦ > 0 for 0 < Φ <

cosΦ = = = = → b

47 - 90 = 43

43 - 180 = x

x = 137

it would open into a square depending on the type of envelope i’m not sure about the second part