Solve the problem by making up an equation. a man could arrive on time for an appointment if he drove the car at 40 mph; however, since he left the house 15 minutes late, he drove the car at 50 mph and arrive 3 minutes early for the appointment. how far from his house was his appointment?

60 miles

Step-by-step explanation:

Let x denote the distance between his home and the place of appointment and t be the time taken by him at 40 mph.

Also,

Since he left the house 15 minutes late, he drove the car at 50 mph and arrive 3 minutes early for the appointment.

15 minutes=

3 minutes=

Then actual time taken by him =t-0.25-0.05=t-0.30

From (1) and (2), we have

Put the value of t in (1), we get

Hence, the distance between his home and the place of appointment = 60 miles.

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answer: b.48 for

step-by-step explanation: