The length of a rectangle plus its width is 24 cm. the area is 143 square cm. what are the length and width of the rectangle?

The rectangle is 13cm by 11cm  (or 11cm by 13cm)

Step-by-step explanation:

Length plus width = 25

L+W = 24

Area is 143

A = LW

143 = LW

We have two equations and two unknowns

L+W = 24    Solve for W  by subtracting L from each side   W = 24-L

143 = LW

Now substitute into the second equation

143 = L(24-L)

Distribute

143 = 24L - L^2

Multiply by -1

-143 = -24L +L^2

-143 = L^2 -24L

Completing the square

-24/2 = -12   -12^2 =144

Add 144 to each side

-143+144 = L^2 -24L+144

1 =   (L-12)^2

Take the square root of each side

±sqrt(1) = sqrt(  (L-12)^2)

±sqrt(1) =   (L-12)

Add 12 to each side

12±sqrt(1) =   (L-12)+12

12±1 = L

13=L   or 11=L

Now we need to find W

W = 24 - L

W = 24-13   W = 24-11

W = 11 or W =13

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;