36x2 + 49y2 = 1,764 the foci are located at: a) (-√13, 0) and (√13,0) b) (0, -√13) and (0,√13) c) (-1, 0) and (1, 0)

The answer is A) (-√13, 0) and (√13,0)

Step-by-step explanation:

Given equation is 36x^2 + 49y^2 = 1,764

We have to find the foci

The above equation can be written as

This equation is of the form of ellipse whose standard equation can be written as

where a  represents the radius of the major axis and b  represents the radius of the minor axis of the ellipse.

By comparing the above two equations, we get

a=7, b=6, h=0 and k=0

The foci of ellipse are (h+c,k) and (h-c,k)

c is the distance from the center to a focus which can be calculated as

Substitute the values to find foci, we get

and

⇒ and

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: