Acollege is selling tickets for a winter fund-raiser. one day, krissa sold 14 adult tickets and 8 student tickets for a total of $376. the next day, she sold 7 adult tickets and 11 student tickets for a total of $272. krissa wanted to find the price of one adult ticket, a, and the price of one student ticket, s. she wrote and solved the following system of equations.

Step-by-step explanation:

Let's solve this by elimination, then substitution.

x= Adult ticket

y= Student ticket

First day: 14x + 8y = 376

Second day: 7x + 11y = 272:

14x+8y=376

7x+11y=272

Divide 14x+8y=376 by -2:

-7x+-4y=-188

7x+11y=272

Eliminate both -7x and 7x:

-4y=-188

11y=272:

Add all numbers:

7y=84

Divide both sides by 7/ divide 84 by 7:

y=12

Now substitute y into one of the equations:

7x+11y=272:

7x+11(12)=272

Simplify:

7x+132=272

Subtract both sides by 132:

7x=140

Divide both sides by 7 (140/7):

x=20

Adult Tickets: $20

Student Tickets: $12

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.