The perimeter of the rectangle is 120 feet. if the length of the rectangle is ten feet more than the width ,what are the dimensions (length and width) of the rectangle?

Hello from MrBillDoesMath!

L = 35, W = 25

Discussion:

The attachment shows that

P = 2L + 2W = 120  

and

L = 10 + W

2L + 2W = 120                => Substitute the last equation into the first one

2(10 + W) + 2W = 120    =>

20 + 2W + 2W = 120     => combine like terms

20 + 4W = 120               => subtract 20 from both sides

4W = 120 -20 = 100      => divide both sides by 4

W = 100/4 = 25

Hence, L = 10 + W = 10 + 25 = 35

Thank you,

MrB

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step-by-step explanation:

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i think asking google will you get the answer to that question