The bottom of ignacio's desktop is 74.5cm from the floor. ignacio's sits in his adjustable chair, and the tops of his legs are 49.3cm from the floor. each clockwise rotation of the knob on the chair raises ignacio's legs by 4.8cm. write an inequality to determine the number of clockwise rotations, r, ignacio could make with the knob without his legs touching the desk

Ignacio can make 5 clockwise rotations.

Step-by-step explanation:

Given that the Ignacio's legs are already at a height of 49.3cm and each rotation of the chair knob raises his legs another 4.8cm, we can set up an inequality to determine the number of rotations Ignacio could make without his legs touching the desk, which is at a height of 74.5cm:

4.8r + 49.3 < 74.5  where 'r' is equal to the number of rotations

The sum of the Ignacio's original leg height plus the amount of height increased from the rotations of the know must be less than 74.5 in order for his legs not to touch.  Now, solve for 'r':

Subtract 49.3 from both sides:  4.8r + 49.3 - 49.3 < 74.5 - 49.3 or 4.8r < 25.2

Divide 4.8 from both sides:  4.8r/4.8 < 25.2/4.8 or  r < 5.25

Since the number of rotations must be less than 5.25, he can make 5 complete rotations.  

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

the surface area is 124cm²

step-by-step explanation:

length: 4cm

width: 9cm

height:   2cm