Need with son's homework i will give 30 ! show work daniel's house is located b miles from his school. the swimming pool is 3 miles farther from his school. his dr. office is 4 miles less than twice the distance from home to daniel's school. a. write an expression that shows the distance from daniel's house to the swimming pool. b. write an expression that shows the distance from daniel's house to his dr's office c. if b=3, is the swimming pool or dr's office closer to daniel's house? how much closer

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.

i dont know sorry

step-by-step explanation: