Arectangle is 8cm longer then it is wide, and it’s area is 153cm^2. find the dimensions of the rectangle.

Width of 9cm and length of 17cm.

Step-by-step explanation:

To calculate an area of a rectangle, use the formula A=l*w. We know the length is 8cm longer than the width. So l = 8 + w. So the area is A= (8+w)*w.

We also know the area is 153. Substitute this value for A and solve.

To solve the quadratic, use the quadratic formula:

Here a=1, b=8 and c=-153.

Since w=9 or w=-17, substitute this value for w in l= 8+w to find l.

l = 8+9 = 17

or

l=8+-17 = -9

Since length cannot be positive, it must be l=17 and w=9.

answer: all the values are within because it has a pattern that repeats from -6 to 4.

good luck!

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph