Find the volume of an object that has the following dimensions. be sure to round off to correct sig figs. 5.00 cm, 3.01 cm, and 3.8 cma)5.7cmb)57 cmc)57.2 cmd)57.cm^3

B

Step-by-step explanation:

The side that is 3.8 cm has only 2 sig digs. So the answer ought to have only 2 sig digs. The only possible answer is

Formula

V = l*w*h

Givens

Solution

V = 5 * 3.01 * 3.8

V = 57.19 cm^3

To two places that's V = 57

Answer B

10% of increase is the final answer! : )