Mathematics, 22.06.2019 10:00 Merlinemicheli4727

If f(x)=x+4/x, g(x)=x-2 and h(x)=4x-1 what is f(h(g(

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Answer from: astultz309459

hello : f(h(g(x)))= (4x - 9) + 4 /(4x - 9)

Step-by-step explanation:

calculate : h(g(x))

h(g(x)) = h(x - 2) = 4 (x -2) -1 = 4x - 8 -1

h(g(x)) = 4x - 9

calculate : f(h(g(x)))

f(h(g(x))) = f (4x - 9) = (4x - 9) + 4 /(4x - 9)

Answer from: Kaylinne1181

f(h(g(x))) = (4x-9)+4/(4x-9)

Step-by-step explanation:

We have given three functions and we have to find their compositions.

f(x) = x+4/x , g(x) = x-2 and h(x) = 4x-1

f(h(g(x))) = ?

Firstly , we have to find h(g(x)).

h(g(x)) = h(x-2)

h(g(x)) = 4(x-2)-1

h(g(x)) = 4x-8-1

h(g(x)) = 4x-9

now find f(h(g(x)))

f(h(g(x))) = f(4x-9)

f(h(g(x))) = (4x-9)+4/(4x-9) which is the answer.

Answer from: Emorej22

$(f\times h\times g)(x)=\frac{4x^3+7x^2+38x+8}{x}$

Step-by-step explanation:

Given : If $f(x)=\frac{x+4}{x}$ , g(x)=x-2 and h(x)=4x-1

To find : What is $(f\times h\times g)(x)$ ?

Solution :

We can write,

$(f\times h\times g)(x)=f(x)\times g(x)\times h(x)$

Substituting the values of the function given,

$(f\times h\times g)(x)=(\frac{x+4}{x})\times (x-2)\times(4x-1)$

$(f\times h\times g)(x)=(\frac{x+4}{x})\times (4x^2-x-8x+2)$

$(f\times h\times g)(x)=(\frac{x+4}{x})\times (4x^2-9x+2)$

$(f\times h\times g)(x)=\frac{x+4}{x}\times 4x^2-\frac{x+4}{x}\times 9x+\frac{x+4}{x}\times 2$

$(f\times h\times g)(x)=4x^2+16x-9x+36+2+\frac{8}{x}$

$(f\times h\times g)(x)=4x^2+7x+38+\frac{8}{x}$

$(f\times h\times g)(x)=\frac{x(4x^2+7x+38)+8}{x}$

$(f\times h\times g)(x)=\frac{4x^3+7x^2+38x+8}{x}$

Therefore, $(f\times h\times g)(x)=\frac{4x^3+7x^2+38x+8}{x}$

Answer from: shadowmatz

(16x² - 72x + 85) / (4x-9)

Step-by-step explanation:

first put g(x) into h(x)

h(g(x)) = 4(x-2) - 1 = 4x - 8 - 1 = 4x - 9, then

f(h(g(x))) = (4x - 9) + (4/4x-9) = ((4x-9)(4x-9) + 4)/(4x-9) =

(16x² - 72x + 81 + 4)/(4x-9) = (16x² - 72x + 85)/(4x-9)

If you are missing parentheses around (x+4)/x, then the answer would be different.

Answer from: gwenparks

(16x² - 72x + 85) / (4x-9)

Step-by-step explanation:

first put g(x) into h(x)

h(g(x)) = 4(x-2) - 1 = 4x - 8 - 1 = 4x - 9, then

f(h(g(x))) = (4x - 9) + (4/4x-9) = ((4x-9)(4x-9) + 4)/(4x-9) =

(16x² - 72x + 81 + 4)/(4x-9) = (16x² - 72x + 85)/(4x-9)

Answer from: blacee01

The answer is B. Hope that helps

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