An object is propelled upward from the top of a 300 foot building. the path that the object takes as it falls to the ground can be modeled by h = 16t^2 + 80t + 300 where t is the time (in seconds) and h is the corresponding height (in feet) of the object. how long does it take the object to hit the ground?

As per the statement:

The path that the object takes as it falls to the ground can be modeled by

where h is the height of the objects and t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

For a quadratic equation:         ......[1]

the solution for the equation is given by:

On comparing the given equation with [1] we have;

a = -16 ,b = 80 and c = 300

then;

Simplify:

sec and sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

the amount you'd have after the work is $1.55

step-by-step explanation:

you subtract 95% from $31.

idk lol

step-by-step explanation: