How many milliliters of olive oil (d=0.92 g/ml) have the same mass as 1.80 l of gasoline (d= .74 g/ml)

1448 mL

Step-by-step explanation:

The mass is the same.

Formula

m = d*V

Givens

Olive Oil

d = 0.92 grams / mL

V = ??

Gasoline

d = 0.74 grams / mL

V = 1.8 L = 1.8 L * (1000 ml / L)

V = 1800 mL

Solution

0.74 * 1800 mL = 0.92 * x                      Divide both sides by 0.92

0.74/0.92 * 1800 mL = 0.92 *x / 0.92   Combine the left

0.8043  * 1800 mL = x

x = 1448 mL

The volume of Olive Oil needed is 1448 mL

4038

step-by-step explanation:

pleaze mark brainliest!

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2